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January 25, 2015

January 25, 2015

Posted by **Francis** on Monday, July 28, 2014 at 8:28am.

Y = 1/SinX^2

- Maths (differentiation) -
**Reiny**, Monday, July 28, 2014 at 9:22amthe way you typed it, Wolfram read it as

http://www.wolframalpha.com/input/?i=+Y+%3D+1%2FSinX%5E2

and y = (sinx)^-2

dy/dx = -2(sinx)^-3 (cosx)

= -2cotx /sin^2 x

or

= -2cotx csc^2 x

if you meant:

y = 1/ sin(x^2)

then y = sin(x^2)^-1

dy/dx = -1sin(x^2)^-2 cos(x^2) (2x)

= -2x cot(x^2) csx(x^2)

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