three point charges are located on the positive y-axis of a coordinate system.charge q1 = -2.09 nC is 2.05 m from the origin and charge q2 = +2.70 nC is 3.25 m from the origin, and the third charge q3 = -2.56 nC is located 5.03 m on the positive y-axis.the fourth charge q4 = -4.06 nC is 3.97 m on the negative y-axis.what is the total force exerted by these charges on charge q5 = -7.43 nC located at the origin.

do coulombs law, add. For each force, location determines the direction of force. so draw a diagram first.

To find the total force exerted on charge q5, we need to calculate the force exerted on q5 by each individual charge and then sum them up vectorially.

The force between two charges can be calculated using Coulomb's Law:

F = k * (|q1 * q2| / r^2)

Where F is the force, k is the electrostatic constant (9 * 10^9 Nm^2/C^2), q1 and q2 are the charges, and r is the distance between the charges.

Let's calculate the force exerted by each charge on q5:

1. Charge q1: q1 = -2.09 nC, r1 = 2.05 m
Using Coulomb's law, the force exerted by q1 on q5 is:
F1 = k * (|q1 * q5| / r1^2)

2. Charge q2: q2 = +2.70 nC, r2 = 3.25 m
Using Coulomb's law, the force exerted by q2 on q5 is:
F2 = k * (|q2 * q5| / r2^2)

3. Charge q3: q3 = -2.56 nC, r3 = 5.03 m
Using Coulomb's law, the force exerted by q3 on q5 is:
F3 = k * (|q3 * q5| / r3^2)

4. Charge q4: q4 = -4.06 nC, r4 = -3.97 m (negative y-axis)
Since q4 is on the negative y-axis, we need to reverse the direction of the force exerted by q4 on q5:
F4 = -k * (|q4 * q5| / r4^2)

Now we can calculate the total force:

Total Force = F1 + F2 + F3 + F4

Plug in the values and calculate the result.