How many mole of gas are present in 25l chamber containing a pressure of 750mmhg at (-)25c?

PV=nRT solve for n, use R with the right units (liter, K, mmHg(torr)) Temps in Kelvins.

-0.001805248

Well, let's shake things up with a little joke before diving into the calculations. Why did the mole go to therapy? Because he couldn't find his chemical balance!

Now, let's get serious. To answer your question, we need to use the Ideal Gas Law equation, PV = nRT, where P is the pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the temperature in Kelvin.

First, let's convert the temperature to Kelvin. We add 273 to -25 to get 248 Kelvin.

Converting the pressure from mmHg to atm, we divide 750 mmHg by 760 (since there are 760 mmHg in 1 atm), giving us approximately 0.9868 atm.

Now let's plug in the values into the Ideal Gas Law equation:

(0.9868 atm)(25 L) = n(0.0821 L·atm/mol·K)(248 K)

Simplifying:

24.67 = 20.4108n

Now, let's solve for n:

n = 24.67 / 20.4108

n ≈ 1.21 moles

So, there are approximately 1.21 moles of gas present in the 25 L chamber at a pressure of 750 mmHg and a temperature of -25°C.

To determine the number of moles of gas present in the 25L chamber, we can use the ideal gas law equation: PV = nRT. This equation relates the pressure (P), volume (V), number of moles (n), gas constant (R), and temperature (T).

However, before we can use this equation, we need to convert the given pressure and temperature to the appropriate units.

The pressure of 750 mmHg needs to be converted to atmospheres (atm). We know that 1 atm is equal to 760 mmHg. Therefore, we can use the conversion factor:

750 mmHg × (1 atm / 760 mmHg) = 0.9868 atm

Next, we need to convert the temperature of -25°C to Kelvin (K). The Kelvin temperature scale is used in the ideal gas law equation. To convert from Celsius to Kelvin, we simply add 273.15 to the given temperature:

-25°C + 273.15 = 248.15 K

Now we have all the required values for the ideal gas law equation:

P = 0.9868 atm
V = 25 L
R = 0.0821 L·atm/(mol·K) (the ideal gas constant)
T = 248.15 K

Rearranging the equation PV = nRT to solve for n:

n = (PV) / (RT)

Let's plug in the values:

n = (0.9868 atm * 25 L) / (0.0821 L·atm/(mol·K) * 248.15 K)

Calculating this equation will give us the number of moles of gas present in the 25L chamber at the given conditions.