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March 30, 2015

March 30, 2015

Posted by **Taylor** on Tuesday, July 22, 2014 at 10:29pm.

f(x)=1/3x-5

y=1/3x-5

x=1/3y-5

x-5=1/3y

y=the square root of x-5/3

- algebra 2 -
**Reiny**, Tuesday, July 22, 2014 at 11:28pmIs this supposed to be the solution to finding the inverse of

y = 1/3x - 5 ???

I suggest a 2-step process

1. interchange the x and y variables

----> x = 1/3y - 5

(you had that)

2. now solve this new equation for y

x = 1/3y - 5

x+5 = 1/3y

times 3

3x + 15 = y

so f^-1 (x) = 3x+15

Why did you involve a square root ??

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