A bullet of mass 20 g moving with a speed of 120 m/s hits a thick muddy wall & penetrates into it. It takes 0.03 s to stop the wall then what is the answer
To determine the answer, we need to calculate the force exerted on the wall by the bullet.
1. We can start by finding the momentum of the bullet before it hits the wall.
Momentum (p) is given by the equation:
p = mass × velocity
Given:
Mass of the bullet (m) = 20 g = 0.02 kg
Velocity of the bullet (v) = 120 m/s
Using the equation, we can calculate the momentum:
p = 0.02 kg × 120 m/s
= 2.4 kg⋅m/s
2. Next, we can determine the force exerted on the wall using the formula:
Force (F) = Change in momentum / Time taken (Δt)
Given:
Time taken to stop the wall (Δt) = 0.03 s
Using the equation, we can calculate the force:
F = (2.4 kg⋅m/s) / 0.03 s
= 80 N
Therefore, the force exerted on the wall by the bullet is 80 Newtons.