Posted by **Elisheva** on Monday, July 21, 2014 at 12:26am.

If 72.4 kJ of heat is supplied to a 752 g block of metal, the temperature of the metal increases by 9.95°C. Calculate the specific heat capacity of the metal in J/g·°C.

I cannot find the information in my textbook, and I don't understand the equation needed to do the work on the summer assignment...

- Honors Chemistry -
**DrBob222**, Monday, July 21, 2014 at 12:51am
q = mc*delta T

q = heat = 72,400J

m = 752g

c = specific heat = ?

dT = 9.95

Solve for c.

- physical chemistry -
**Bb**, Thursday, August 14, 2014 at 11:54pm
q = mcdT

72 400 = 752 X C X 9.95

C = 9.676 J/C

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