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March 6, 2015

March 6, 2015

Posted by **Anonymous** on Sunday, July 20, 2014 at 10:35pm.

- Math -
**Steve**, Monday, July 21, 2014 at 12:29am28' = 853.44 cm

18' = 548.64 cm

Easy way, assuming partial pieces are tucked in as needed:

(853*548)/(60*40) = 195

Now, you can do several kinds of approximation, requiring whole pieces, etc. One easy way is to round up the lawn area to multiples of 40 and 60:

853/60 = 14.2, round up to 15

548/40 = 13.7, round up to 14

So, the lawn is about 15 by 14 sods in size, requiring 210 pieces.

The actual optimal value is somewhere in between those two values.

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