Monday

January 26, 2015

January 26, 2015

Posted by **Anonymous** on Sunday, July 20, 2014 at 10:35pm.

- Math -
**Steve**, Monday, July 21, 2014 at 12:29am28' = 853.44 cm

18' = 548.64 cm

Easy way, assuming partial pieces are tucked in as needed:

(853*548)/(60*40) = 195

Now, you can do several kinds of approximation, requiring whole pieces, etc. One easy way is to round up the lawn area to multiples of 40 and 60:

853/60 = 14.2, round up to 15

548/40 = 13.7, round up to 14

So, the lawn is about 15 by 14 sods in size, requiring 210 pieces.

The actual optimal value is somewhere in between those two values.

**Answer this Question**

**Related Questions**

Math - A homeowner is laying sod in her lawn. The lawn is a rectangle with ...

Geometry - Joel is laying pipe for a sprinkler system before he plants his lawn....

math - In order for you to put down new sod in the front yard you will need ...

Algebra - Lisa, Nicole, and Amber are to mow a rectangular lawn that measures ...

Statistical - A botany student counted 11 blades of grass in one square ...

math - Nala and her cousin agreed that they would each mow one-half of the lawn...

Math - A rectangle has a width of 4 cm and a height of 3 cm. If another ...

Math - Venski and his brother have each agreed to mow half of the front lawn, ...

math 4 grade - Mr.Sports wants to buy enough sod for his new field is 16 feet,...

Algebra Word Problem - A rectangle has dimensions of 12x8inches. If a uniform ...