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September 30, 2014

September 30, 2014

Posted by **alex** on Sunday, July 20, 2014 at 9:04pm.

- physics -
**Steve**, Monday, July 21, 2014 at 5:01amconsider the takeoff to be at (0,0). The height of the skier is thus

y = vt - 4.9t^2

maximum height is thus reached at t = v/9.8

y(v/9.8) = v*v/9.8 - 4.9(v/9.8)^2

= v^2/9.8 - v^2/(4*4.9)

= v^2/9.8 (1 - 1/2)

= v^2/19.6

Since the max height is directly proportional to the square of the takeoff velocity, the ratio of the max heights achieved by Fred and George is (20/8.5)^2

Since you give no data regarding the angle of takeoff, we cannot calculate any absolute values, but we do have the ratio.

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