10L of hard water required 5.6g of lime for removing hardness. hence temporary hardness in ppm of cac03.
The answer 1000ppm
I really want all tutors to solve it form clearly step by step.
Thank a lot
hard water? Do you mean has dissolved calcium carbonate? Then why would one add lime, lime is the source of hardness.
I have no idea what this problem statement means
To solve this problem step by step, you need to use the formula:
Temporary Hardness (ppm) = (Amount of Lime used in grams ÷ Volume of Water in liters) × 1000
Given:
Amount of Lime used = 5.6 grams
Volume of Water = 10 liters
Step 1:
Plug in the given values into the formula:
Temporary Hardness (ppm) = (5.6 grams ÷ 10 liters) × 1000
Step 2:
Perform the division:
Temporary Hardness (ppm) = (0.56 grams per liter) × 1000
Step 3:
Multiply the result by 1000:
Temporary Hardness (ppm) = 560 grams per liter
Step 4:
Convert grams per liter to parts per million (ppm):
Temporary Hardness (ppm) = 560 ppm
Therefore, the temporary hardness is 560 ppm.