Posted by Taylor on Sunday, July 20, 2014 at 10:11am.
3/y2 1/y=4/y^2y
3y/y^2y  y/y^2y=4/y^2y
3yy=4
2y=4
y=2

algebra 2  bobpursley, Sunday, July 20, 2014 at 1:50pm
Put y =2 in the original equation on each side, and see if each side equals the other side.

algebra 2  Steve, Sunday, July 20, 2014 at 3:54pm
y=2 should immediately be discarded, since fractions with y2 in the denominator are not defined.
The steps should be
3y/y(y2)  (y2)/y(y2) = 4/y(y2)
3yy+2 = 4
2y = 2
y = 1
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