evaluate
5x^2+3xy-y^2
when x=3 and y=-3
5(3^2) + 3(3)(-3) - (-3)2
= 45 - 27 - 9
= 9
6x2-y2-3xy if X=-2 and y=4
To evaluate the expression 5x^2+3xy-y^2 when x=3 and y=-3, follow these steps:
Step 1: Replace x with 3 and y with -3 in the expression.
5(3)^2 + 3(3)(-3) - (-3)^2
Step 2: Simplify the exponents and perform the calculations.
5(9) + 3(-9) - 9
Step 3: Multiply and add/subtract the numbers.
45 - 27 - 9
Step 4: Perform the remaining calculations.
9 - 9 = 0
Therefore, when x = 3 and y = -3, the expression 5x^2+3xy-y^2 evaluates to 0.
To evaluate the expression 5x^2 + 3xy - y^2 when x = 3 and y = -3, follow these steps:
Step 1: Start with the given expression: 5x^2 + 3xy - y^2.
Step 2: Replace every instance of x with 3 and every instance of y with -3.
So, the expression becomes: 5(3)^2 + 3(3)(-3) - (-3)^2.
Step 3: Simplify the exponents: 5(9) + 3(3)(-3) - 9.
Step 4: Perform the multiplication and addition/subtraction: 45 - 27 - 9.
Step 5: Continue to simplify: 45 - 36.
Step 6: Perform the final subtraction: 9.
Therefore, when x = 3 and y = -3, the value of the expression 5x^2 + 3xy - y^2 is 9.