Monday

March 30, 2015

March 30, 2015

Posted by **cbse 8th** on Saturday, July 12, 2014 at 12:59am.

x=4/5(x+10)

2x/3+1=7x/15+3

2y+5/3=26/3-y

3m=5m-8/5

- maths needed fastly -
**MathMate**, Saturday, July 12, 2014 at 6:02amI'll solve one, and will let you try the others as exercise.

x=(4/5)(x+10)

multiply by (5/4) on both sides:

5x/4 = x+10

subtract x from each side

5x/4-x =10

x/4=10

x=40

Check:

(4/5)(x+10)=(4/5)(40+10)=40=x ok.

**Answer this Question**

**Related Questions**

maths-urgently needed[Differential equations] - solve- dy/dx = 2xy + (y^2/x^2)

maths-urgently needed[Differential equations] - solve- dy/dx = 2xy + (y^2/x^2)

maths pls help - 1. Solve the following simultaneous equations: log2 xy = 7 log2...

maths - solve the following pair of simultaneous equations. 2x-3y=13 3x+y=3

Maths - Solve Graphically the following simultaneous linear equations 5x+7y=13 ...

Maths - Solve Graphically the following simultaneous linear equations 2y-3x=12 x...

maths - solve the following simultaneous equations using matrices 3x-6y=24 and -...

MATH - Please help me!!!!!!!!!!!!!!!1 Instructions a. If needed, rewrite the ...

Maths - 'a' and 'b'are integers and (a, b) = 2. Solve the following two ...

Xuha's Guideline Center (maths) - Solve graphically the following simultaneous ...