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April 30, 2016
Posted by **cbse 8th** on Saturday, July 12, 2014 at 12:59am.

x=4/5(x+10)

2x/3+1=7x/15+3

2y+5/3=26/3-y

3m=5m-8/5

- maths needed fastly -
**MathMate**, Saturday, July 12, 2014 at 6:02amI'll solve one, and will let you try the others as exercise.

x=(4/5)(x+10)

multiply by (5/4) on both sides:

5x/4 = x+10

subtract x from each side

5x/4-x =10

x/4=10

x=40

Check:

(4/5)(x+10)=(4/5)(40+10)=40=x ok.