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maths needed fastly

posted by on .

solve the following equations
x=4/5(x+10)
2x/3+1=7x/15+3
2y+5/3=26/3-y
3m=5m-8/5

  • maths needed fastly - ,

    I'll solve one, and will let you try the others as exercise.

    x=(4/5)(x+10)
    multiply by (5/4) on both sides:
    5x/4 = x+10
    subtract x from each side
    5x/4-x =10
    x/4=10
    x=40

    Check:
    (4/5)(x+10)=(4/5)(40+10)=40=x ok.

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