Post a New Question

chemistry step by step thank a lot

posted by .

Al2(s04)3 solution of a molal concentration is present in 1 litre solution of 2.684g/cc. How many moles of bas04 would be precipitated on adding bacl2 in excess?
the answer 6M

Who helps me step by step for me clearly
I am thankful to all tutors

  • chemistry step by step thank a lot -

    Al2(SO4)3 +3BaCl2 >> 3BaSO4 (s) + 2AlCl3

    first, figure out the number of moles per liter of aluminum sulfate there are in 2.684Kg.

    You will get three times that number of moles of BaSO4 (look at the balanced equation).

Answer This Question

First Name:
School Subject:
Answer:

Related Questions

More Related Questions

Post a New Question