Whoops I meant ..
Sqrt of x+3, not x+1..
(a+b)^2 = a^2 + ab + b^2
a+b)^2 = a^2 + 2ab + b^2
(sqrt of 4x+1)+(sqrt of x+3)=2
4x+1 + 2 (sqrt (x+3)sqrt(4x+1)) + x+3=4
5x+4 +2 (sqrt (5x+4)=4
square both sides
x=-12/5 or x=6/5
Hmmm. I get
4x+1 + 2√(4x^2+13x+3) + x+3 = 4
5x = -2√(4x^2+13x+3)
25x^2 = 4(4x^2+13x+3)
25x^2 = 16x^2 + 52x + 12
9x^2 - 52x - 12 = 0
(9x+2)(x-6) = 0
x = -2/9 , 6
But x=6 does not satisfy the original equation, so -2/9 is the only solution.
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