Tuesday

January 27, 2015

January 27, 2015

Posted by **sally** on Friday, July 11, 2014 at 11:13am.

In the near-Earth orbit the rate of change of momentum is (v/R)p = (v/R)mv

- science -
**sally**, Friday, July 11, 2014 at 11:40amand how does it go from there to this

In the near-Earth orbit the rate of change of momentum is (v/R)p = (v/R)mv toward the center of the Earth, and this must equal the gravitational force GMm/R2, so

mv2/R = GMm/R2, and

mv2 = GMm/R.

Therefore in this orbit

K+U = (1/2)mv2 - GMm/R = -(1/2)GMm/R

This is a negative number reflecting the fact that this is a bound state. To minimize the work required to move the satellite far away, we want the final kinetic energy to be zero, and if it is far away the gravitational potential energy is also zero. Since the change in K+U is equal to the work we do, we have

0 - (-(1/2)GMm/R) = W, so

W = (1/2)GMm/R.

**Answer this Question**

**Related Questions**

physics - What is the ratio of the spin angular momentum of the earth and its ...

Physics please HELP - What is the ratio of the spin angular momentum of the ...

Please help with Physics Quickly - 1. How are impulse and momentum related? (...

Science - Explain how a parachutist's loss of momentum on landing is consistent ...

Physics - drwls? - A 2000 kg truck traveling north at 38 km/hr turns east and ...

Physics - I think I chose the correct answer. In a closed system, two carts have...

Science - We are studying energy my questions What happens to the momentum of a ...

Physics - A billiard ball of mass m = 0.250 kg hits the cushion of a billiard ...

Physics - Angular Momentum - When the angular momentum changes, the 'change' in ...

physics - Identical forces act for the same length of time on two different ...