Posted by **EMMA** on Friday, July 11, 2014 at 8:03am.

a 100kg street light is supported equally by two ropes. one rope pulls up and to the right 40 degrees above the horizontal; the other pulls up and to the left 40 degrees . what is the tension of the rope?

- PHYSICS -
**Henry**, Thursday, July 16, 2015 at 9:06pm
M*g = 100kg * 9.8N./kg = 980 N. = Wt. of

st. light.

T1*Cos(180-40) + T2*Cos40 = -980*cos270.

-0.766T1 + 0.766T2 = 0.

0.766T2 = 0.766T1.

T1 = T2.

T1*sin(180-40) + T2*sin40 = -980*sin270.

0.643T1 + 0.643T2 = 980.

Replace T2 with T1:

0.643T1 + 0.643T1 = 980.

1.286T1 = 980.

T1 = 762 N. = T2.

- PHYSICS -
**Henry**, Thursday, July 16, 2015 at 9:22pm
Or T1 = T2.

T1*sin(180-40) + T1*sin40 = -980*sin270.

0.643T1 + 0.643T1 = 980.

1.286T1 = 980.

T1 = 762 N. = T2.

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