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December 28, 2014

December 28, 2014

Posted by **lindsay** on Thursday, July 10, 2014 at 10:24am.

3 log x = 1 + log (4x+5)/ log 2

- math -
**Steve**, Thursday, July 10, 2014 at 10:51am3 log x = 1 + log (4x+5)/ log 2

That dividing logs stuff is quite unusual for introductory log problems. I will solve

3 log x = 1 + log (4x+5) - log 2

x^3 = 10*(4x+5)/2

2x^3-40x-50 = 0

2(x-5)(x^2+5x+5) = 0

and that's easy

If you really did mean to divide the logs, then I cannot find any real roots.

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