Tuesday

September 16, 2014

September 16, 2014

Posted by **lindsay** on Thursday, July 10, 2014 at 10:22am.

- math -
**Steve**, Thursday, July 10, 2014 at 10:44am10^(2x+1) -7(10^x) -26 = 0

10*10^2x - 7*10^x - 26 = 0

10*10^(2*2log t) - 7*10^(2log t) - 26 = 0

10*10^(4log t) - 7*10^(2log t) - 26 = 0

10*(10^(log t))^4 - 7*(10^(log t))^2 - 26 = 0

10t^4 - 7t^2 - 26 = 0

(10t^2+13))(t^2-2) = 0

t = ±√2 or ±√(13/10) i

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