Posted by lindsay on .
Given that x = 2log t is a solution of the equation10^(2x+1) 7(10^x) 26 =0. Find t

math 
Steve,
10^(2x+1) 7(10^x) 26 = 0
10*10^2x  7*10^x  26 = 0
10*10^(2*2log t)  7*10^(2log t)  26 = 0
10*10^(4log t)  7*10^(2log t)  26 = 0
10*(10^(log t))^4  7*(10^(log t))^2  26 = 0
10t^4  7t^2  26 = 0
(10t^2+13))(t^22) = 0
t = ±√2 or ±√(13/10) i