Friday

August 1, 2014

August 1, 2014

Posted by **chandler** on Thursday, July 10, 2014 at 12:14am.

- statistics -
**PsyDAG**, Friday, July 11, 2014 at 5:45pmZ = (score-mean)/SEm

SEm = SD/√n

Find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability between the two Z scores.

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