When using the normal approximation to the binomial, what is the mean used in the standardization formula when approximating a binomial distribution with 123 trials and p=0.35? Please submit your answer with 2 decimal places

To use the normal approximation to the binomial distribution, you need to find the mean and standard deviation of the corresponding normal distribution. The mean of a binomial distribution is given by μ = np, where n is the number of trials and p is the probability of success.

In this case, the number of trials is given as 123 and the probability of success is 0.35. Therefore, the mean can be calculated as follows:

μ = np = 123 * 0.35

Calculating this:

μ = 43.05

So, the mean used in the standardization formula for the normal approximation to the binomial distribution with 123 trials and p=0.35 is 43.05 (rounded to 2 decimal places).