Posted by Anonymous on .
Find the equation of the tangent line to the graph of f(x) = 6x ln(x + 4) at x = 2.

Urgent Calculus Help 2 
Damon,
dy/dx = 6x d/dx [ln(x+4)]+ 6 ln(x+4)
= 6 x /(x+4) + 6 ln(x+4)
so at x = 2
dy/dx = slope = m = 12/ln(6) + 6 ln (6)
but ln (6) = 1.79
so use that to find the slope m
then we have
y = m x + b and we know m
find y at x = 2
y= 12 (1.79) = 21.5
so use that
21.5 = 2 m + b
we know m, solve for b
the end 
Urgent Calculus Help 2 
Anonymous,
Thank you!

Urgent Calculus Help 2 
Damon,
You are welcome.