Friday
July 25, 2014

Homework Help: Chemistry

Posted by Luke on Wednesday, July 9, 2014 at 4:26pm.

A mixture of ammonia and oxygen is prepared by combining 0.250 L of NH3 (measured at 0.700 atm and 20C) with 0.160 L of O2 (measured at 0.720 atm and 49C). How many milliliters of N2 (measured at 0.740 atm and 100. C) could be formed if the following reaction occurs?

4NH3(g) + 3O2(g) -->2N2(g) + 6H2O(g)

I get that oxygen is the limiting factor
For NH3 I get n=.00727
For o2 I get n= .00435
So I do 3/2 x .00435 =.0029
Then .740atm x L = .0029 x .0821 x 373
Then .0888/.740 =.120
Does this look right?

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