Posted by **Kiara** on Wednesday, July 9, 2014 at 4:03pm.

Explain, without doing any calculations, why there cannot be a Real solution to the equation

p5 + 2x2 + 3px + 7 + 8 = -2:

- Algebra II - Bogus -
**Steve**, Wednesday, July 9, 2014 at 4:06pm
I suspect typos. The function is littered with junk.

p?

+7+8?

- Algebra II -
**Reiny**, Wednesday, July 9, 2014 at 4:14pm
I will assume p5 is meant to be p^5

and 2x2 is meant to be 2x^2 , then

p^5 + 2x^2 + 3px + 17 = 0

2x^2 + 3px + p^5 + 17 = 0

a quadratic with a = 2 , b = 3p and c = p^5 + 17

for real roots:

9p^2 - 4(2)(p^5 + 17) ≥ 0

9p^2 - 8p^5 - 136 ≥ 0

using Wolfram to solve, I got p < -1.69

http://www.wolframalpha.com/input/?i=9p%5E2+-+8p%5E5+-+136+%3D+0

check your typing, as long as p < -1.69 you will have 2 real solutions each time

## Answer This Question

## Related Questions

- Algebra - Determine the number of real-number solutions to the equation -2x2 - x...
- Algebra - Solve. (–10x3 + 30x – 20) ÷ (–5x + 5) • 2x2 – 2x + 4 • –2x2 – 2x – 4...
- college algebra - Find all real solutions of the equation. (Enter your answers ...
- algebra,math - Solve the equation. Check both solutions and only write the real ...
- Algebra - How can you tell an equation's real or imaginary roots just from its ...
- College Algebra - Consider only the discriminant, b2 - 4ac, to determine whether...
- Math 117 Algebra - for the following equation, state the value of the ...
- College Algebra 2 - for the following equation state the value of the ...
- algebra - solve the equation. Enter the answer as a comma-separated list. if ...
- Algebra 2 - What are the real and complex solutions of the polynomial equation? ...

More Related Questions