a man of 80kg is supported by a two cables then t1 and t2 is
To find the tension in cables T1 and T2, we need to consider the equilibrium of forces acting on the man.
Let's assume that the cables make angles θ1 and θ2 with the vertical direction.
The weight of the man is acting vertically downward and can be represented by the force W, which is equal to the mass (m) of the man multiplied by the acceleration due to gravity (g). So, W = m * g.
Now let's consider the forces acting in the horizontal (x) and vertical (y) directions:
In the x-direction, the tension in cable T2 will balance the horizontal component of the weight. Since there is no other force acting horizontally, T2 = W * sin(θ2).
In the y-direction, the sum of the vertical components of the tensions in cables T1 and T2 will balance the vertical component of the weight. Mathematically, T1 * cos(θ1) + T2 * cos(θ2) = W * cos(0°) (since the weight acts vertically down).
However, since we know that T1 + T2 = W, we can rewrite the equation as:
T1 + T2 * cos(θ2) = W * cos(0°).
Now, substituting the value of W with m * g, we get:
T1 + T2 * cos(θ2) = m * g * cos(0°).
Given that an individual's weight is 80 kg and the acceleration due to gravity is approximately 9.8 m/s², we can substitute these values into the equation to find the values of T1 and T2, but we also need the values of angles θ1 and θ2 to calculate the precise values.