Two resistors Ra= 1.95 ohms and Rb = 0.05 ohms are connected in parallel and take a total of 50A. What is the current trough each resistor.
r = R1 R2 / (R1+R2) = 1.95*.05 /2 = .04875
In other words if connected in parallel, the .05 resistor carries practically all the current.
V = 50 *.04875 = 2.4375 volts
i through .05 = 2.4375/.05 = 48.75 amps
i through 1.95 = 2.4375/1.95 = 1.25 amps
yawa
Nice i forgot the formula for the unequal resistor in a parallel connection ty
Ohm my goodness, let's do some electrifying calculations here!
When resistors are connected in parallel, the total current flowing through the circuit is divided among them. To find the current flowing through each resistor, we can use the formula:
1/Rt = 1/Ra + 1/Rb
1/Rt = 1/1.95 + 1/0.05
1/Rt = 0.51282 + 20
1/Rt = 20.51282
Rt = 1/20.51282
Rt = 0.0488 ohms (approximately)
Now let's calculate the current flowing through each resistor using Ohm's Law (I = V/R):
For Ra:
Ia = V/Ra
Ia = 50A (total current) * (Ra / Rt)
Ia = 50A * (1.95 ohms / 0.0488 ohms)
Ia = 1996.72A (approximately)
For Rb:
Ib = V/Rb
Ib = 50A (total current) * (Rb / Rt)
Ib = 50A * (0.05 ohms / 0.0488 ohms)
Ib = 102.46A (approximately)
So, the current flowing through resistor Ra is approximately 1996.72A, and the current flowing through resistor Rb is approximately 102.46A.
Please be aware that these values are quite high, so handle those resistors with care!
To find the current through each resistor in a parallel circuit, you can use the formula:
1/Total Resistance = 1/Ra + 1/Rb
First, let's calculate the total resistance:
1/Total Resistance = 1/Ra + 1/Rb
1/Total Resistance = 1/1.95 + 1/0.05
Now we can find the value of the total resistance:
1/Total Resistance = (0.0513 + 20)
1/Total Resistance = 0.0518
Taking the reciprocal of both sides, we find:
Total Resistance = 19.2847 ohms
Now, we can find the current through each resistor by using Ohm's law:
Current (I) = Voltage (V) / Resistance (R)
Since the total current (Itotal) is given as 50A, we can divide it between the two resistors:
Itotal = Ia + Ib
Solving for Ia and Ib:
Ia = Itotal * (Ra / Total Resistance)
Ib = Itotal * (Rb / Total Resistance)
Substituting the values:
Ia = 50 * (1.95 / 19.2847)
Ib = 50 * (0.05 / 19.2847)
Now let's calculate them:
Ia ≈ 1.28A
Ib ≈ 0.13A
Therefore, the current through resistor Ra is approximately 1.28A and the current through resistor Rb is approximately 0.13A.