Sunday

February 1, 2015

February 1, 2015

Posted by **Colby** on Sunday, July 6, 2014 at 1:32pm.

I found the Z-score: 82-80/5

Which gave me .6554 then 1-.6554=.3446

So 34% would make a 82 or more

- statistics -
**PsyDAG**, Sunday, July 6, 2014 at 2:03pmYou are looking for a distribution of means rather than raw scores.

Z = (score-mean)/SEm

SEm = SD/√n

Now go to your Z table.

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