Post a New Question

posted by tuhi on Sunday, July 6, 2014 at 12:42pm.

find the zeroes of : p(x)= X^2 + 2 root2x + 6

x^2 + 2√2 x + 6 = 0 use the good old quadratic formula: x = (-2√2 ± √(8-24))/2 = (-2√2 ± 4i)/2 = -√2 ± 2i

More Related Questions