Dylan hangs a calendar on a refrigerator with a magnetic hook. Unfortunately, the magnet is too weak, so the magnet and calendar slide down the side of the refrigerator to the floor with an acceleration of magnitude 3ms2. If the coefficient of sliding friction between the magnet and the refrigerator is 0.1, what is the magnitude of the total vertical force the refrigerator exerts on the magnet? The mass of the magnet is 0.05kg and the mass of the calendar is 0.1kg. There is no contact between the calendar and the refrigerator.

If needed, g=10ms2.

You can take the system of calendar-magnet and you have :

W1+W2-T=(m1+m2)*a=> T = 1.05 N

Then, T=ì*N=>N=10.5N must be the answer you are looking for.

this answer is wrong

To find the magnitude of the total vertical force that the refrigerator exerts on the magnet, we need to consider the forces acting on the system.

Let's break down the problem step by step:

1. Determine the gravitational force acting on each object:
The gravitational force is given by the equation F_gravity = m * g, where m is the mass and g is the acceleration due to gravity. Given that the mass of the magnet is 0.05 kg and the mass of the calendar is 0.1 kg, and g is 10 m/s^2, we can calculate the gravitational force on each object:

For the magnet:
F_gravity_magnet = 0.05 kg * 10 m/s^2 = 0.5 N

For the calendar:
F_gravity_calendar = 0.1 kg * 10 m/s^2 = 1 N

2. Determine the force of sliding friction:
The force of sliding friction can be calculated using the equation F_friction = μ * N, where μ is the coefficient of sliding friction and N is the normal force exerted on the object by the surface. In this case, since the only horizontal force acting on the system is the force of sliding friction, the force of sliding friction will be equal to the net horizontal force of the system.

Given that the coefficient of sliding friction is 0.1, the normal force exerted on the magnet is equal to its weight, so the force of sliding friction can be calculated as:

F_friction = 0.1 * F_gravity_magnet = 0.1 * 0.5 N = 0.05 N

3. Calculate the net vertical force on the system:
Since the magnet and calendar are sliding down the side of the refrigerator, the total vertical force on the system can be found by subtracting the force of friction from the gravitational force on the calendar:

Net vertical force = F_gravity_calendar - F_friction = 1 N - 0.05 N = 0.95 N

Therefore, the magnitude of the total vertical force that the refrigerator exerts on the magnet is 0.95 N.