Posted by **Richard** on Sunday, July 6, 2014 at 1:20am.

What is the value of each of the angles of a triangle whose sides are 95, 150, 190 cm in length?

I have tried to do this problem, don't get me wrong, but I don't really know where to go. Can someone tell me how to even approach this problem?

The textbook states that the answers are: 99 degrees opposite the 190 cm side; 3*10 degrees opposite the 95 cm side; 51 degrees opposite the 95 cm side.

That being said, I would still like to know how to do this problem.

- Physics -
**Richard**, Sunday, July 6, 2014 at 1:21am
Sorry, there was a typo. *51 degrees opposite the 150 cm side.

- Physics -
**Damon**, Sunday, July 6, 2014 at 4:45am
use law of cosines

a = 95

b = 150

c = 190

c^2 = a^2 + b^2 - 2 a b cos C

36100 = 9025 + 22500 - 28500 cos C

28500 cos C = -4575

cos C = -.16053

C = 99.2 degrees

now use law of sine to find the next one

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