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November 23, 2014

Homework Help: chemistry step for step thank a lot

Posted by ken on Saturday, July 5, 2014 at 8:56pm.

10L of hard water required 5.6g of lime for removing hardness. Hence temporary hardness in ppm of cac03.
The answer 1000

I think ppm= 1mg/1L
10L x 100g/mol cac03 = 1000

Who check it for me step by step
Thank all tutors for your help.

How many ml of a 0.05M kmno4 solution are required to oxide 2g of fes04 in a dilute solution.

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