Gasoline producers add oxygenated chemical compounds to reduce the amount of carbon monoxide produced when the fuel is burned. Methyl t-butyl ether (MTBE) is one such oxygenate that is no longer used because of health and environmental concerns. what are the correct exponents for a balanced chemical reaction when MTBE is burned in the presence of oxygen.
I presume it's just like any other hydrocarbon; i.e., products are CO2 and H2O
Understanding the strengths of carbon halogen bonds can help us to understand the behavior of CFCs and related molecules. Arrange the members of the set of carbon halogen bonds shown below in the order of bond strength.
A) carbon dioxide B) methane C) ozone D)water
A)
c > b > a > d
B)
a > b > c > d
C)
d > a > b > c
D)
c > b > d > a
Thanks, this is not homework...just trying to understand the problems in the back of the book before the test
To determine the correct exponents for a balanced chemical reaction when MTBE (methyl t-butyl ether) is burned in the presence of oxygen, we need to write the balanced chemical equation.
Let's start by writing the chemical formula for MTBE:
MTBE: C5H12O
Next, let's write the chemical formula for oxygen:
Oxygen: O2
The combustion of MTBE in the presence of oxygen will produce carbon dioxide (CO2) and water (H2O). The balanced chemical equation is:
C5H12O + O2 → CO2 + H2O
To balance this equation, we need to ensure that there are an equal number of atoms of each element on both sides of the equation.
Balancing the carbon (C) atoms:
On the reactant side, we have 5 carbon atoms in MTBE, and on the product side, we have only 1 carbon atom in CO2. So, to balance the carbon atoms, we need to put a coefficient of 5 in front of CO2:
C5H12O + O2 → 5CO2 + H2O
Balancing the hydrogen (H) atoms:
On the reactant side, we have 12 hydrogen atoms in MTBE, and on the product side, we have only 2 hydrogen atoms in H2O. So, to balance the hydrogen atoms, we need to put a coefficient of 6 in front of H2O:
C5H12O + O2 → 5CO2 + 6H2O
Balancing the oxygen (O) atoms:
On the reactant side, we have 2 oxygen atoms in MTBE and O2, and on the product side, we have 10 oxygen atoms in CO2 and H2O. So, to balance the oxygen atoms, we need to put a coefficient of 5 in front of O2:
C5H12O + 5O2 → 5CO2 + 6H2O
Therefore, the correct exponents for a balanced chemical reaction when MTBE is burned in the presence of oxygen are: 1, 5, 5, 6.