what volume of hcl solution of density 1.2g/cm3 and containing 36.5% by weight hcl, must be allowed to react with zinc in order to liberate 4g of hydrogen
I know this calculate this part, but I do not get the answer 333.3ml
1.2g/ml x 1000 x 0.365/36.5 = 12M
or other calculation
0.365x 1200/36.5 =12M
But I do not understand to get 333.3ml answer Pls step by step for me
How 12 M came
To calculate the volume of HCl solution needed to liberate 4g of hydrogen, you can follow these steps:
Step 1: Calculate the molar mass of HCl:
The molar mass of HCl is 1.008 g/mol (hydrogen) + 35.453 g/mol (chlorine) = 36.461 g/mol.
Step 2: Calculate the number of moles of HCl in 4g of hydrogen:
To do this, divide the mass of the hydrogen (4g) by the molar mass of HCl (36.461 g/mol):
4g / 36.461 g/mol = 0.1095 mol.
Step 3: Calculate the volume of the HCl solution using the molarity equation:
Molarity (M) = moles (mol) / volume (L).
Given that the solution is 12M, you can rearrange the equation to solve for the volume:
Volume (L) = moles (mol) / Molarity (M).
Using the moles of HCl calculated in Step 2 (0.1095 mol):
Volume (L) = 0.1095 mol / 12 M = 0.009125 L.
Step 4: Convert the volume to milliliters (mL):
Since 1 L is equivalent to 1000 mL, we can multiply the volume in liters by 1000 to get the answer in milliliters:
0.009125 L * 1000 = 9.125 mL.
Therefore, the volume of HCl solution needed to liberate 4g of hydrogen is approximately 9.125 mL.
To find the volume of the HCl solution needed, we can use the following steps:
Step 1: Calculate the moles of hydrogen gas (H2) from the given mass of hydrogen.
Given:
Mass of hydrogen (H2) = 4g
Since one mole of H2 contains 2 grams of hydrogen, we can find the moles of H2:
moles of H2 = mass of H2 / molar mass of H2
molar mass of H2 = 2g/mol
moles of H2 = 4g / 2g/mol = 2 mol
Step 2: Determine the stoichiometry of the reaction between HCl and Zn.
The balanced chemical equation for the reaction is:
Zn + 2HCl -> ZnCl2 + H2
From the equation, we can see that one mole of Zn reacts with 2 moles of HCl to produce one mole of H2. Therefore, we need 2 moles of HCl per mole of H2.
Step 3: Calculate the volume of the HCl solution required.
To convert moles of HCl to volume, we need to use the molarity (M) of the HCl solution.
Given:
Density of the HCl solution = 1.2 g/cm3
Percent by weight of HCl = 36.5%
Molar mass of HCl = 36.5 g/mol
We need to convert the given density to molarity. This requires converting the grams of HCl to moles and dividing it by the volume in liters.
First, let's find the mass of HCl present in 1 liter of the HCl solution.
Mass of HCl in 1 liter of solution = 1.2 g/cm3 x 1000 cm3/L = 1200 g/L
Now, calculate the moles of HCl present in 1 liter of the solution:
moles of HCl = mass of HCl / molar mass of HCl
moles of HCl = 1200 g / 36.5 g/mol ≈ 32.9 mol/L
To find the volume of the HCl solution required to obtain 2 moles of HCl, we can use the following calculation:
Volume of HCl solution (in liters) = moles of HCl needed / molarity of HCl solution
Volume of HCl solution = 2 mol / 32.9 mol/L ≈ 0.061 L
Since 1 L = 1000 mL, we can convert the volume to milliliters:
Volume of HCl solution = 0.061 L x 1000 mL/L ≈ 61.0 mL
The calculated volume is approximately 61.0 mL. Therefore, the answer should be 61.0 mL, not 333.3 mL as stated earlier.
I did it step by step. Here it is again with more explanation. Write and balance the equation.
Zn + 2HCl ==> H2 + ZnCl2
How many mols H2 do you want to generate. mols = grams/molar mass
g H2 = 4g. molar mass H2 = 1*2 = 2 g/mol.
mol H2 = 4g/2 = 2 mols H2 in 4g H2.
Now convert mols H2 to mols HCl. That is done with the coefficient in the balanced equation.
2 mols H2 x (2 mols HCl/1 mol H2) = 4 mols HCl To obtain 4g H2 (2 mol) you will need 4 mols HCl.
How much 12 M HCl does it take to get 4 mol HCl? M HCl = mols HCl/L HCl or rearrange to L HCl = mols HCl/M HCl.
mols HCl = 4
M HCl = 12
L HCl = 4/12 = .3333L = 333.3 mL.