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December 20, 2014

December 20, 2014

Posted by **solomon** on Friday, July 4, 2014 at 1:09pm.

q(x)=-x^2(x+1)^2(x-2)

- algebra -
**Steve**, Friday, July 4, 2014 at 2:52pmsince there are two double roots, the graph is tangent to the x-axis at 0 and -1. It crosses only at x=2.

So, since it is a 5th degree polynomial, with leading coefficient negative, it rises at the left end and falls on the right end.

So,

q > 0 for x < -1

q > 0 for -1 < x < 0

q > 0 for 0 < x < 2

q < 0 for x > 2

To confirm this, see the graph at

http://www.wolframalpha.com/input/?i=-x^2%28x%2B1%29^2%28x-2%29+for+-1.5+%3C+x+%3C+2.1

- algebra -
**solomon**, Saturday, July 5, 2014 at 9:27amwhat are the zeros and multiplicity? and the Range of the equation?

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