Posted by **raghavendra** on Friday, July 4, 2014 at 6:26am.

The magnitude of two vectors p and q differ by 1. The magnitude of their resultant makes an angle of tan inverse ( 3 / 4 ) with p. The angle between p and q is

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**Steve**, Friday, July 4, 2014 at 10:56am
hmmm...

If θ is the angle between p+q and p, cosθ = 4/5

If Ø is the angle between p+q and q, then the angle between p and q is θ+Ø

Let's let |q| = a, so |p| = a+1

p•q = a(a+1)cos(θ+Ø)

(p+q)•p = |p+q|*|p| cosθ = (4/5)(a+1)|p+q|

(p+q)•q = |p+q|*|q| cosØ = |p+q|(a) cosØ

|p+q| = pcosθ + qcosØ = (4/5)(a+1) + acosØ

Somewhere in those equations you can surely solve for a and Ø, and you want θ+Ø.

Play around with that, while I do the same.

Or, there may be a handy formula I have forgotten.

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