A solution of hydrogen peroxide, H2O2, is titrated with potassium permanganate, KMnO4, according to the following equation: 5H2O2 + 2KMnO4 + 3H2SO4 = 5O2 + 2MnSO4 + 8H2O + K2SO4. It requires 46.0 mL of 0.145 Mol/L KMnO4 to titrate 50.0 mL of the solution of H2O2. What is the mole per liter concentration of H2O2 in the solution?

http://www.jiskha.com/display.cgi?id=1404360366

Brett, I worked these problems for you earlier.

To find the molarity of the hydrogen peroxide (H2O2) solution, we can use the given information about the volume and concentration of the potassium permanganate (KMnO4) used in the titration.

The balanced equation for the reaction tells us that the ratio between KMnO4 and H2O2 is 2:5. Therefore, the moles of KMnO4 used in the titration can be calculated as follows:

moles KMnO4 = concentration KMnO4 * volume KMnO4
= 0.145 Mol/L * 0.0460 L
= 0.00667 mol

According to the equation, 2 moles of KMnO4 react with 5 moles of H2O2. Therefore, the moles of H2O2 in the solution can be calculated as follows:

moles H2O2 = (moles KMnO4 / 2) * 5
= (0.00667 mol / 2) * 5
= 0.0167 mol

To find the molarity of H2O2, we need to divide the moles of H2O2 by the volume of the H2O2 solution in liters:

molarity H2O2 = moles H2O2 / volume H2O2
= 0.0167 mol / 0.0500 L
= 0.334 Mol/L

Therefore, the molarity of the H2O2 solution is 0.334 Mol/L.