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March 28, 2017

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A spherical snowball melts in such a way that its surface area decreases at a rate of 1 cm2/min. Find the rate at which its diameter is decreasing when the diameter is 10 cm

  • Calculus 1 - ,

    A = 4 pi r^2
    r = D/2
    so
    A = 4 pi D^2/4 = pi D^2
    dA/dD = 2 pi D
    dA/dt = 2 pi dD/dt

    1 = 2 pi dD/dt
    dD/dt = 1/(2pi)

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