Posted by michael R 43 on Thursday, July 3, 2014 at 11:11am.
Steve for the two answer you gave me could you show me more detail how you came up with answers please Thanks

Algebra  Steve, Thursday, July 3, 2014 at 11:44am
another way is called elimination. You have
5x  9y = 7
7y  3x = 5
Rearrange terms a bit to get
5x  9y = 7
3x + 7y = 5
To get rid of the x values, find the LCM of 5 and 3: 15. Now multiply things a bit to get
15x  27y = 21
15x + 35y = 25
Now you can add the two equations and the x terms disappear:
8y = 4
y = 1/2
Now substitute that into either equation, and solve for x.
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