Posted by michael R 43 on .
Steve for the two answer you gave me could you show me more detail how you came up with answers please Thanks

Algebra 
Steve,
another way is called elimination. You have
5x  9y = 7
7y  3x = 5
Rearrange terms a bit to get
5x  9y = 7
3x + 7y = 5
To get rid of the x values, find the LCM of 5 and 3: 15. Now multiply things a bit to get
15x  27y = 21
15x + 35y = 25
Now you can add the two equations and the x terms disappear:
8y = 4
y = 1/2
Now substitute that into either equation, and solve for x.