A solution of hydrogen peroxide, H2O2, is titrated with potassium permanganate, KMnO4, according to the following equation: 5H2O2 + 2KMnO4 + 3H2SO4 = 5O2 + 2MnSO4 + 8H2O + K2SO4. It requires 46.0 mL of 0.145 Mol/L KMnO4 to titrate 50.0 mL of the solution of H2O2. What is the mole per liter concentration of H2O2 in the solution?
mols KMnO4 = M x L = ?
Use the coefficients in the balanced equation to convert mols KMnO4 to mols H2O2.
Then M H2O2 = mols H2O2/L H2O2 I'll be glad to check your answer.
To find the molar concentration of H2O2 in the solution, we can use the stoichiometry of the balanced equation.
Given:
Volume of KMnO4 solution (V1) = 46.0 mL
Molar concentration of KMnO4 solution (C1) = 0.145 Mol/L
Volume of H2O2 solution (V2) = 50.0 mL
From the balanced equation, we know that the stoichiometric ratio between KMnO4 and H2O2 is 2:5. This means that 2 moles of KMnO4 react with 5 moles of H2O2.
First, let's find the number of moles of KMnO4 used in the titration using the given volume and concentration:
moles of KMnO4 (n1) = C1 * V1 (using the formula: moles = concentration * volume)
= 0.145 Mol/L * 0.0460 L (converting mL to L)
= 0.00667 mol
Next, using the stoichiometric ratio, we can determine the number of moles of H2O2 present in the titrated solution:
moles of H2O2 (n2) = (5/2) * n1 (using the stoichiometric ratio)
= (5/2) * 0.00667 mol
= 0.0167 mol
Finally, to find the molar concentration of H2O2 in the solution, we divide the number of moles by the volume of the H2O2 solution:
Molar concentration of H2O2 (C2) = n2/V2 (using the formula: concentration = moles/volume)
= 0.0167 mol / 0.0500 L (converting mL to L)
= 0.334 M
So, the molar concentration of H2O2 in the solution is 0.334 mol/L.
To find the molar concentration of H2O2 in the solution, we can use the concept of stoichiometry to relate the amount of KMnO4 used to the amount of H2O2 present.
First, let's gather the necessary information from the problem:
Volume of KMnO4 used (V1) = 46.0 mL
Concentration of KMnO4 (C1) = 0.145 Mol/L
Volume of H2O2 solution (V2) = 50.0 mL
To determine the molar concentration of H2O2 (C2), we can use the equation:
(C1)(V1) = (C2)(V2)
Substituting the given values, we have:
(0.145 Mol/L)(46.0 mL) = (C2)(50.0 mL)
Now, let's solve for C2:
C2 = (0.145 Mol/L)(46.0 mL) / (50.0 mL)
C2 = (0.145 Mol)(46.0) / 0.05
C2 = 6.67 Mol/L
Therefore, the molar concentration of H2O2 in the solution is approximately 6.67 Mol/L.