Posted by Bethany on Wednesday, July 2, 2014 at 11:43pm.
The sum of integrs from 4060, inclusive, is 1050. What is the aum of the integers from 6080, inclusive?
I figured out the answer by adding them with a calculator but i was wondering if there was an algebraic way of solving this?

Math  Steve, Thursday, July 3, 2014 at 12:15am
Since you are adding 20 to each number, just add 20*21 to the total.
Or, thinking of the values as an arithmetic progression, recall that the sum of n terms is
Sn = n/2 (T1+Tn)
With a=40,d=1,
S21 = 21/2 (40+60) = 1050
With a=60,d=1,
S21 = 21/2 (60+80) = 1470
Note that 1470 = 1050 + 21*20

Math  Bethany, Thursday, July 3, 2014 at 12:26am
Ok, thank you!
Answer This Question
Related Questions
 Math  The sum of the integers from 40 to 60, inclusive, is 1050. what is the ...
 Math  The sum of the integers from 40 to 60, inclusive, is 1050. what is the ...
 Math  the sum of the integers from 1 to 10, inclusive, is 55. What is the sum ...
 algebra  The sum of the first n counting numbers 1 + 2 + 3 + 4 + 5 ... + n is ...
 Geometry  I am having a little trouble understanding this... could someone help...
 Math  In an arithmetic series, the sum of the 5th to the 8th terms inclusive is...
 Math ( Number Theory )  How many numbers from 1 to 1000 inclusive can be ...
 Math  Find the sum of all integers between 1200 and 2900, inclusive, which are...
 SAT math  Set M consists of the consecutive integers from 15 to y, inclusive. ...
 SAT prep help  Set M consists of the consecutive integers from 15 to y, ...
More Related Questions