Posted by 123HG on Wednesday, July 2, 2014 at 10:20pm.
A flowerpot falls from a window sill 37.7 m
above the sidewalk.
What is the velocity of the flowerpot when
it strikes the ground? The acceleration of
gravity is 9.81 m/s2 .
Can you tell me the steps and why?

Physics  123HG, Wednesday, July 2, 2014 at 10:23pm
***FORGOT TO ASK
How much time does a passerby on the side
walk below have to move out of the way before
the flowerpot hits the ground?
Answer in units of s
explain please?

Physics  MathMate, Thursday, July 3, 2014 at 6:38am
For the velocity, equation PE and KE.
PE=KE
mgh = (1/2)mv²
and solve for v.
(both g and h are negative, y is positive upwards)
For time, use
y=vi*t+(1/2)at²
for vi=0, equation simplifies to
y=(1/2)at²
(Notice that both y and g are negative)
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