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Physics

posted by on .

A flowerpot falls from a window sill 37.7 m
above the sidewalk.
What is the velocity of the flowerpot when
it strikes the ground? The acceleration of
gravity is 9.81 m/s2 .

Can you tell me the steps and why?

  • Physics - ,

    ***FORGOT TO ASK

    How much time does a passerby on the side-
    walk below have to move out of the way before
    the flowerpot hits the ground?
    Answer in units of s

    explain please?

  • Physics - ,

    For the velocity, equation PE and KE.
    PE=KE
    mgh = (1/2)mv²
    and solve for v.
    (both g and h are negative, y is positive upwards)

    For time, use
    y=vi*t+(1/2)at²
    for vi=0, equation simplifies to
    y=(1/2)at²
    (Notice that both y and g are negative)

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