Posted by **123HG** on Wednesday, July 2, 2014 at 10:20pm.

A flowerpot falls from a window sill 37.7 m

above the sidewalk.

What is the velocity of the flowerpot when

it strikes the ground? The acceleration of

gravity is 9.81 m/s2 .

Can you tell me the steps and why?

- Physics -
**123HG**, Wednesday, July 2, 2014 at 10:23pm
***FORGOT TO ASK

How much time does a passerby on the side-

walk below have to move out of the way before

the flowerpot hits the ground?

Answer in units of s

explain please?

- Physics -
**MathMate**, Thursday, July 3, 2014 at 6:38am
For the velocity, equation PE and KE.

PE=KE

**mgh = (1/2)mv²**

and solve for v.

(both g and h are negative, y is positive upwards)

For time, use

**y=vi*t+(1/2)at²**

for vi=0, equation simplifies to

y=(1/2)at²

(Notice that both y and g are negative)

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