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October 31, 2014

October 31, 2014

Posted by **rachel** on Wednesday, July 2, 2014 at 3:57pm.

- math -
**Steve**, Wednesday, July 2, 2014 at 5:23pmlook up you standard form for

∫√(u^2-a^2) du

Now, if you let u = 2x, you have

u^2 = 4x^2

du = 2 dx, so dx = du/2

Also, let a = √3

So, now your integral is

15/2 ∫√(u^2-a^2) du

and just go for it.

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