a+b+c+d+e = 35 (mean=7)
c = 7 (median)
e = a+7 (range)
a+b+7+d+a+7 = 35
2a+b+d = 21
If a=1, b+d=19
But b<=7 and e=8
But, if b<=7, and d<=8, no go
If a=2, b+d=17
same problem as above
If a=3, b+d=15
d<=10, so b>=5
so we can have
If a=4, b+d=13
d <= 11, so b>=2. In fact, we know b>=4, so we can have
If a=5, b+d=11
no go, since b>=5, meaning d<=6, but d must be at least 7.
So, only the sets in boldface above are candidates.
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