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June 30, 2016
Posted by **sophia** on Wednesday, July 2, 2014 at 2:58pm.

- math (?) -
**PsyDAG**, Wednesday, July 2, 2014 at 5:28pmWhat properties?

- math -
**Steve**, Wednesday, July 2, 2014 at 5:39pma+b+c+d+e = 35 (mean=7)

c = 7 (median)

e = a+7 (range)

a+b+7+d+a+7 = 35

2a+b+d = 21

If a=1, b+d=19

But b<=7 and e=8

1,b,7,d,8

But, if b<=7, and d<=8, no go

If a=2, b+d=17

2,b,7,d,9

same problem as above

If a=3, b+d=15

d<=10, so b>=5

so we can have

3,b,7,d,10 as**3,5,7,10,10**

3,6,7,9,10

3,7,7,8,10

If a=4, b+d=13

d <= 11, so b>=2. In fact, we know b>=4, so we can have

4,b,7,d,11**4,4,7,9,11**

4,5,7,8,11

If a=5, b+d=11

d<=12,

5,b,7,d,12

no go, since b>=5, meaning d<=6, but d must be at least 7.

So, only the sets in boldface above are candidates.