In a hardware store the ratio of shovels to rakes is 3:5. If there are 10 more rakes than shovels, how many rakes are there in the hardware store?

I know shovels = r-10 but don't know where to go from there?

if there are 8x tools, then there are 3x shovels and 5x rakes. So,

5x = 3x+10
x=5

so, there are 15 shovels and 25 rakes

Well, it seems like this hardware store is really digging its way into some raking issues! Anyway, let's try to solve this problem.

Since the ratio of shovels to rakes is 3:5, we can write it as a fraction and simplify it: 3/5.

Now, let's assume the number of shovels in the hardware store is "x". That means the number of rakes would be "x + 10" because there are 10 more rakes than shovels.

So, we can set up the equation 3/5 = x/(x + 10) to represent the ratio.

To solve this equation, we can cross-multiply: 3(x + 10) = 5x.

Expanding the left side gives us 3x + 30 = 5x. Subtracting 3x from both sides gives us 30 = 2x. Finally, dividing both sides by 2 gives us x = 15.

Since x represents the number of shovels, there are 15 shovels in the hardware store.

Remember, we also found that the number of rakes is x + 10. So, x + 10 = 15 + 10 = 25.

Therefore, there are 25 rakes in the hardware store.

Hope this answer tickles your funny bone while digging deep into the world of ratios and hardware stores!

To solve this problem, let's assign variables to represent the number of shovels and rakes in the hardware store.

Let the number of shovels be "x", and the number of rakes be "y".

According to the given information, the ratio of shovels to rakes is 3:5. So we can set up the equation:

x/y = 3/5

We are also told that there are 10 more rakes than shovels, so another equation we can set up is:

y = x + 10

Now, we can solve this system of equations. We'll start by rearranging the second equation:

x = y - 10

Substituting this value into the first equation:

(y - 10) / y = 3/5

Cross-multiply:

5(y - 10) = 3y

Expand:

5y - 50 = 3y

Subtract 3y from both sides:

5y - 3y - 50 = 0

2y - 50 = 0

Add 50 to both sides:

2y = 50

Divide by 2:

y = 25

Therefore, there are 25 rakes in the hardware store.

To solve this problem, let's first assign variables to the number of shovels and rakes in the hardware store.

Let's call the number of shovels "s" and the number of rakes "r".

Given that the ratio of shovels to rakes is 3:5, we can write the equation:
s/r = 3/5.

We also know that there are 10 more rakes than shovels, which can be represented as:
r = s + 10.

Now, we can use this information to solve for the number of rakes in the hardware store.

Let's substitute the second equation into the first equation to eliminate the variable "r" and solve for "s".

s / (s + 10) = 3/5.

Next, cross-multiply to get rid of the fractions:
5s = 3(s + 10).

Distribute on the right side of the equation:
5s = 3s + 30.

Simplify:
2s = 30.

Now, divide both sides of the equation by 2 to solve for "s":
s = 30 / 2 = 15.

Therefore, we know that there are 15 shovels in the hardware store.

To find the number of rakes, substitute the value of "s" back into one of the previously given equations:
r = s + 10 = 15 + 10 = 25.

So, there are 25 rakes in the hardware store.