determine the % of water of crystallization in pure sample of green vitriol (FeSo4.7H2O)
Dear shashank,
The chemical formula of FeSo4.7H2O
= 55.8+ 32.1+ 16x4 + 7x18
= 277.9
The percentage of water of crystallization=
= (7x18)/ 277.9 x 100%
= 45.34%
good answer
To determine the percentage of water of crystallization in green vitriol (FeSO4.7H2O), you need to calculate the difference in the weight of the hydrated compound (FeSO4.7H2O) and the anhydrous compound (FeSO4).
Here's a step-by-step guide:
1. Calculate the molar mass of FeSO4.7H2O:
- Molar mass of Fe = 55.845 g/mol
- Molar mass of S = 32.06 g/mol
- Molar mass of O = 16.00 g/mol
- Molar mass of H = 1.008 g/mol
- Therefore, molar mass of FeSO4.7H2O = (55.845 + 32.06 + 4 * 16.00 + 7 * (2.016 + 16.00)) g/mol
- Calculate this value to find the molar mass.
2. Calculate the molar mass of FeSO4:
- Molar mass of FeSO4 = (55.845 + 32.06 + 4 * 16.00) g/mol
- Calculate this value to find the molar mass.
3. Find the difference in molar mass between FeSO4.7H2O and FeSO4:
- Δmolar mass = molar mass of FeSO4.7H2O - molar mass of FeSO4
- Calculate this value.
4. Determine the molar mass of water:
- The molar mass of water (H2O) is 18.015 g/mol.
5. Calculate the moles of water in FeSO4.7H2O:
- Moles of water = Δmolar mass / molar mass of water
6. Calculate the weight of water in FeSO4.7H2O:
- Weight of water = moles of water * molar mass of water
7. Calculate the percentage of water of crystallization:
- Percentage of water of crystallization = (Weight of water / Weight of FeSO4.7H2O) * 100
By following these steps and performing the necessary calculations, you can determine the percentage of water of crystallization in the pure sample of green vitriol (FeSO4.7H2O).