What per cent of free s03 can be obtained from 100g oleum, that is labeled with 113.5% h2s04?

To 100 ml of 5M naoh solution density 1.2g/ml were added 200ml of another naoh solution with have a density 1.5g/ml and contains 20 mass percent of naoh. What is the concentration of resulting naoh solution obtained by mixing above two naoh solution

Who step by step for me clearly

To calculate the percentage of free SO3 obtained from 100g of oleum, which is labeled with 113.5% H2SO4, we need to follow these steps:

Step 1: Calculate the amount of H2SO4 in the oleum:
Given that oleum is labeled with 113.5% H2SO4, we can calculate the weight of H2SO4. Since 100g of oleum is used, the weight of H2SO4 can be calculated as:
Weight of H2SO4 = (113.5/100) * 100g = 113.5g

Step 2: Calculate the molecular weight of H2SO4:
The molecular weight of H2SO4 can be calculated by adding the atomic weights of the individual elements:
Molecular weight of H2SO4 = (2 * Atomic weight of hydrogen) + Atomic weight of sulfur + (4 * Atomic weight of oxygen)
Approximately, the atomic weight of hydrogen = 1g/mol, sulfur = 32g/mol, and oxygen = 16g/mol.
So, the molecular weight of H2SO4 is:
Molecular weight of H2SO4 = (2 * 1) + 32 + (4 * 16) = 98g/mol

Step 3: Calculate the molar amount of H2SO4:
Using the given weight of H2SO4, we can calculate the number of moles:
Moles of H2SO4 = Weight of H2SO4 / Molecular weight of H2SO4
Moles of H2SO4 = 113.5g / 98g/mol = 1.157 mol

Step 4: Calculate the molar amount of SO3:
For each mole of H2SO4, 1 mole of SO3 is produced. Hence, the molar amount of SO3 is equal to the molar amount of H2SO4, which is 1.157 mol.

Step 5: Calculate the mass of SO3:
The molecular weight of SO3 is approximately 80g/mol. We can calculate the mass of SO3 using the molar amount and molecular weight:
Mass of SO3 = Moles of SO3 * Molecular weight of SO3
Mass of SO3 = 1.157 mol * 80 g/mol = 92.56g

Step 6: Calculate the percentage of free SO3:
To calculate the percentage of free SO3, we divide the mass of SO3 obtained by the weight of oleum used and multiply by 100:
Percentage of free SO3 = (Mass of SO3 / Weight of oleum) * 100
Percentage of free SO3 = (92.56g / 100g) * 100 = 92.56%

Therefore, approximately 92.56% of free SO3 can be obtained from 100g of oleum labeled with 113.5% H2SO4.

Now, let's proceed to the second question.

To find the concentration of the resulting NaOH solution obtained by mixing two NaOH solutions, we can follow these steps:

Step 1: Calculate the amount of NaOH in the first solution:
Given that we have 100 ml of 5M NaOH solution, the amount of NaOH can be calculated using the molarity and volume of the solution:
Amount of NaOH in the first solution = Molarity * Volume
Amount of NaOH in the first solution = 5M * 100 ml = 500 moles of NaOH

Step 2: Calculate the amount of NaOH in the second solution:
The second solution has a density of 1.5g/ml and a concentration of 20% NaOH (mass percent).
First, calculate the weight of the second solution:
Weight of the second solution = Density * Volume
Weight of the second solution = 1.5g/ml * 200 ml = 300g

Next, calculate the amount of NaOH in the second solution:
Amount of NaOH in the second solution = Weight of the second solution * Concentration of NaOH
Amount of NaOH in the second solution = 300g * 20/100 = 60g

Step 3: Calculate the total amount of NaOH in the resulting solution:
Total amount of NaOH = Amount of NaOH in the first solution + Amount of NaOH in the second solution
Total amount of NaOH = 500 moles + 60g

Step 4: Calculate the final volume of the resulting solution:
The total volume of the resulting solution is the sum of the volumes of the two solutions used.
Total volume of the resulting solution = 100 ml + 200 ml = 300 ml

Step 5: Calculate the concentration of the resulting NaOH solution:
Concentration = Total amount of NaOH / Total volume of the resulting solution

Now you can substitute the values in Step 3 and Step 4 to get the concentration of the resulting NaOH solution.

Sure! I can help you with that. Let's break down each question step by step:

Question 1: What per cent of free SO3 can be obtained from 100g oleum, that is labeled with 113.5% H2SO4?

Step 1: Calculate the weight of H2SO4 in oleum:
Weight of H2SO4 = (Percentage of H2SO4/100) * Weight of Oleum

Weight of H2SO4 = (113.5/100) * 100g
Weight of H2SO4 = 113.5g

Step 2: Calculate the molecular weight of H2SO4:
Molecular weight H2SO4 = 2(Atomic weight of Hydrogen) + Atomic weight of Sulfur + 4(Atomic weight of Oxygen)

Molecular weight H2SO4 = 2(1 g/mol) + 32 g/mol + 4(16 g/mol)
Molecular weight H2SO4 = 98 g/mol

Step 3: Calculate the number of moles of H2SO4:
Number of moles = Weight of H2SO4 / Molecular weight H2SO4

Number of moles = 113.5 g / 98 g/mol
Number of moles = 1.16 mol

Step 4: Calculate the number of moles of SO3:
From the balanced chemical equation, we know that each H2SO4 molecule produces 1 SO3 molecule. Therefore, the number of moles of SO3 is equal to the number of moles of H2SO4.

Number of moles of SO3 = 1.16 mol

Step 5: Calculate the weight of SO3 produced:
Weight of SO3 = Number of moles of SO3 * Molecular weight SO3

The molecular weight of SO3 = 3*(Oxygen's atomic weight) = 3*(16 g/mol) = 48 g/mol

Weight of SO3 = 1.16 mol * 48 g/mol
Weight of SO3 = 55.68 g

Step 6: Calculate the percentage of free SO3:
Percentage of free SO3 = (Weight of free SO3 / Weight of Oleum) * 100

Percentage of free SO3 = (55.68 g / 100 g) * 100
Percentage of free SO3 = 55.68%

Therefore, approximately 55.68% of free SO3 can be obtained from 100g of oleum labeled with 113.5% H2SO4.

Now, let's move on to the next question:

Question 2: To 100 ml of 5M NaOH solution (density 1.2 g/ml) were added 200 ml of another NaOH solution which has a density of 1.5 g/ml and contains 20% mass percent of NaOH. What is the concentration of the resulting NaOH solution obtained by mixing the above two NaOH solutions?

Step 1: Calculate the weight of the NaOH in the 1st solution:
Weight of NaOH = Volume of Solution * Density * Mass Percent

Weight of NaOH = 100 ml * 1.2 g/ml * 100% (since the 1st solution is 100% NaOH)
Weight of NaOH = 120 g

Step 2: Calculate the weight of the NaOH in the 2nd solution:
Weight of NaOH = Volume of Solution * Density * Mass Percent

Weight of NaOH = 200 ml * 1.5 g/ml * 20% (since the 2nd solution has 20% NaOH)
Weight of NaOH = 60 g

Step 3: Calculate the total weight of NaOH after mixing:
Total Weight of NaOH = Weight of NaOH in 1st Solution + Weight of NaOH in 2nd Solution

Total Weight of NaOH = 120 g + 60 g
Total Weight of NaOH = 180 g

Step 4: Calculate the total volume of the resulting solution:
Total Volume of Resulting Solution = Volume of 1st Solution + Volume of 2nd Solution

Total Volume of Resulting Solution = 100 ml + 200 ml
Total Volume of Resulting Solution = 300 ml

Step 5: Calculate the concentration of the resulting NaOH solution:
Concentration = (Total Weight of NaOH / Total Volume of Resulting Solution) * 1000

Concentration = (180 g / 300 ml) * 1000
Concentration = 600 g/L

Therefore, the concentration of the resulting NaOH solution obtained by mixing the two NaOH solutions is 600 g/L.