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March 28, 2015

March 28, 2015

Posted by **love** on Sunday, June 29, 2014 at 9:59am.

- statistics (?) -
**PsyDAG**, Sunday, June 29, 2014 at 3:25pmSample data missing.

For the value needed, find table in the back of your statistics text labeled something like "areas under normal distribution" to find the proportion/probability of the outliers on each of both ends (.05, .025, .005) and the Z score.

90% = mean ± 1.645 SEm

95% = mean ± 1.96 SEm

99% = mean ± 2.575 SEm

SEm = SD/√n

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