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March 6, 2015

March 6, 2015

Posted by **Anonymous** on Sunday, June 29, 2014 at 8:57am.

- pre-cal - incomplete -
**Steve**, Sunday, June 29, 2014 at 1:00pmSo the helicopter drops 400 feet. How high was it when it started its descent?

what is "the vehicle"? Is it a car driving directly underneath the chopper?

Did we start at t=0 when the chopper was directly above "the vehicle"?

Which angle of depression? chopper-to-ground? chopper-to-fixed point on ground? chopper-to-moving "vehicle"?

Woefully incomplete conditions!

- pre-cal -
**Steve**, Sunday, June 29, 2014 at 4:45pmHowever, assuming the chopper starts at (0,h) and the vehicle starts at (0,0),

after t minutes the chopper and vehicle are at

(2640t,h - 5/33 t) and

(4224t,0)

So, the line between them has slope

(h-5/33 t)/(1584t)

Now you have the angle

tanθ = (h-5/33 t)/(1584t)

so you can figure dθ/dt at t=10.

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