A 2.73 kg particle has a velocity of vx = 6.02 m/s and vy = 0.316 m/s.

Find the magnitude of its total momentum. Answer in units of kg · m/s

First convert velocities to their resultant vector:

v=sqrt(vx²+vy²)
=6.03 m/s

Momentum=mass*velocity
= 2.73 kg * 6.03 m/s
= 16.5 kg-m/s

To find the magnitude of the total momentum, we can use the formula:

Magnitude of momentum = √(px² + py²)

where px is the momentum in the x-direction and py is the momentum in the y-direction.

First, let's calculate the momentum in each direction:

Momentum in the x-direction (px) = mass * velocity in the x-direction
px = (2.73 kg) * (6.02 m/s) = 16.4686 kg·m/s

Momentum in the y-direction (py) = mass * velocity in the y-direction
py = (2.73 kg) * (0.316 m/s) = 0.86268 kg·m/s

Now, we can calculate the magnitude of the total momentum:

Magnitude of momentum = √(px² + py²)
Magnitude of momentum = √((16.4686 kg·m/s)² + (0.86268 kg·m/s)²)
Magnitude of momentum = √(271.18466596 kg²·m²/s² + 0.7451071984 kg²·m²/s²)
Magnitude of momentum = √(271.9297731584 kg²·m²/s²)
Magnitude of momentum ≈ 16.482 kg·m/s

Therefore, the magnitude of the total momentum is approximately 16.482 kg·m/s.