10. Develop a C++ program that accepts the name of a person and then counts how many vowels the person’s name have.
YES
I NEED A ANSWER
Hussen
To develop a C++ program that counts the number of vowels in a person's name, you can follow these steps:
Step 1: Include the necessary header files.
```cpp
#include <iostream>
#include <string>
using namespace std;
```
Step 2: Declare the main function.
```cpp
int main() {
// code goes here
return 0;
}
```
Step 3: Declare a variable to store the person's name.
```cpp
string name;
```
Step 4: Prompt the user to enter the person's name.
```cpp
cout << "Enter a name: ";
cin >> name;
```
Step 5: Declare a variable to track the number of vowels found and initialize it to zero.
```cpp
int vowelCount = 0;
```
Step 6: Iterate through each character in the name and check if it is a vowel.
```cpp
for (char c : name) {
// Check if the character is a vowel
if (c == 'a' || c == 'e' || c == 'i' || c == 'o' || c == 'u' ||
c == 'A' || c == 'E' || c == 'I' || c == 'O' || c == 'U') {
vowelCount++;
}
}
```
Step 7: Print the number of vowels found.
```cpp
cout << "Number of vowels: " << vowelCount << endl;
```
Step 8: End the program.
```cpp
return 0;
```
The complete program looks like this:
```cpp
#include <iostream>
#include <string>
using namespace std;
int main() {
string name;
cout << "Enter a name: ";
cin >> name;
int vowelCount = 0;
for (char c : name) {
if (c == 'a' || c == 'e' || c == 'i' || c == 'o' || c == 'u' ||
c == 'A' || c == 'E' || c == 'I' || c == 'O' || c == 'U') {
vowelCount++;
}
}
cout << "Number of vowels: " << vowelCount << endl;
return 0;
}
```
By following these steps, you can develop a C++ program that accepts a person's name and counts the number of vowels in it.