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January 25, 2015

January 25, 2015

Posted by **Kaylee** on Tuesday, June 24, 2014 at 10:23pm.

an additional 0.077 m? Answer in units of J

- physics -
**MathMate**, Wednesday, June 25, 2014 at 7:12amUsing the equation for spring potential energy

W=(1/2)kx²

so

ΔW=(1/2)k(x2²-x1²)

=(1/2)(30 N/m)*(0.96²-0.19²)

=13.3 J

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